Array.prototype.map()
The map()
method creates
a new array populated with the results of calling a provided function on
every element in the calling array.
Syntax
// Arrow function
map((element) => { /* … */ })
map((element, index) => { /* … */ })
map((element, index, array) => { /* … */ })
// Callback function
map(callbackFn)
map(callbackFn, thisArg)
// Inline callback function
map(function (element) { /* … */ })
map(function (element, index) { /* … */ })
map(function (element, index, array) { /* … */ })
map(function (element, index, array) { /* … */ }, thisArg)
Parameters
callbackFn
: A function to execute for each element in the array. Its return value is added as a single element in the new array.
The function is called with the following arguments:
element
- : The current element being processed in the array.
index
- : The index of the current element being processed in the array.
array
- : The array
map()
was called upon.
- : The array
thisArg
optional- : A value to use as
this
when executingcallbackFn
.
- : A value to use as
Return value
A new array with each element being the result of the callback function.
Description
The map()
method is an iterative method. It calls a provided callbackFn
function once for each element in an array and constructs a new array from the results.
callbackFn
is invoked only for array indexes which have assigned values. It is not invoked for empty slots in sparse arrays.
The map()
method is a copying method. It does not alter this
. However, the function provided as callbackFn
can mutate the array. Note, however, that the length of the array is saved before the first invocation of callbackFn
. Therefore:
callbackFn
will not visit any elements added beyond the array's initial length when the call tomap()
began.- Changes to already-visited indexes do not cause
callbackFn
to be invoked on them again. - If an existing, yet-unvisited element of the array is changed by
callbackFn
, its value passed to thecallbackFn
will be the value at the time that element gets visited. Deleted elements are not visited.
The map()
method is generic. It only expects the this
value to have a length
property and integer-keyed properties.
Since map
builds a new array, calling it without using the returned
array is an anti-pattern; use Array.prototype.forEach()
or
for...of
instead.